Hi, DATA = [ [ 0 for i in range(ncolumns) ] for i in range(nrows) ]
Is one way. DON'T do it like this: row = [0] * ncolumns data = [ row ] * nrows # WRONG! Since after that, every row is the exact same object; if you set data[0][0] = 1, the first element of _every_ row is 1. But I guess you already found out about that :-) That said, are you sure a list of lists is the best data structure for what you're trying to do? I keep being surprised by Python code that uses other data structures in clever ways; lists of lists seem to be pretty rare! Remco Gerlich On Dec 6, 2007 4:29 PM, Horacius ReX <[EMAIL PROTECTED]> wrote: > in python, when I want to use arrays, I follow this way; > > DATA = [0] * nint > > and when I want to use I do; > > .... > > DATA[i] = .... > > do you know how to do similar but in two dimensions ? > > thanks > -- > http://mail.python.org/mailman/listinfo/python-list >
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