On Dec 3, 3:13 pm, Tim Chase <[EMAIL PROTECTED]> wrote: > > Here is sample function: > > > def a(): > > b() b() is not being assigned to anything. Use c = b() to have c assigned in the local scope. > > print c > > > def b(): When you enter the function b, you are creating a new local scope. c disappears once the function returns. The value of c is returned, however, so if you assign a variable to b(), the value of c will be available. If you require assignment in the global scope, you *must* use the global keyword. That is bad practice, though. > > c = "Hi" > > return c > > > if __name__ == "__main__": > > a() > > > then run a(). Throws error about c not being defined. How do I return c from > > b? > > you *do* return c from b, and within the scope of a(), c is not > defined (within scope) as the error informs you. > > However when you call b(), you don't do anything with its return > value. Try > > def a(): > result = b() # do something with the returned value > print result > > yes, there's also a "global" keyword, but it uglifies code and > logic-flow horribily. > > -tkc
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