> I'm sure I one read somewhere that there is a simple way to set the order
> of replacements withing a string *without* using a dictionary.
>
> What I mean is:
>>>> s = "%s and %s" % ( "A", "B" )
>>>> print s
> A and B
>
> Now, is there something quick like:
>>>> s = "%s/2 and %s/1" % ( "A", "B" )
>>>> print s
> B and A
>
> ?
>
> I know it can be done with a dict:
> d = { "one" : "A", "two" : "B" }
> s = "%(two)s and %(one)s" % d
Well, if you're willing to cheat and use dictionary formatting
where your keys are the number you want (you've gotta have some
syntax for the index notation...why not reuse
dictionary-key/value syntax), you can do something like:
>>> number = lambda x: dict((str(i+1), v) for (i,v) in enumerate(x))
>>> "%(2)s and %(1)s" % number(["A", "B"])
'B and A'
If you don't mind zero-based indices, you can skip the "+1" bit.
-tkc
--
http://mail.python.org/mailman/listinfo/python-list
