John can you make an example of this solution? You maen that a more compact way is possible???
Firma Gianmaria Iaculo "John Machin" <[EMAIL PROTECTED]> ha scritto nel messaggio news:[EMAIL PROTECTED] > On Nov 29, 8:05 am, "Gianmaria Iaculo - NVENTA" > <[EMAIL PROTECTED]> wrote: >> Txs all, >> i wont to respond to who asked why i needed it: >> >> I'm using python on GSM modules and the informations i have to move goes >> along GPRS/UMTS connections so it's beatiful for me to transfer more >> informations with less space... >> imagine i have to send this simple data.... >> >> 41.232323,12.345678 >> >> i can send it as it's or use the nibble trick and on the receiving >> station >> 'unlift" the data and rebuild the original information... >> >> isn'it??? > > Sorry, but it's not apparent what you propose to do. If each number > has 8 decimal digits of precision (as in your example), you could > possibly get by with a 32-bit floating point number. If it's always 6 > decimal places and 0 <= number < 1000, you could pack (number * > 1000000) into a 32-bit integer. For the above two options, check out > the struct module. OTOH, maybe it's "packed decimal" that you mean -- > try Googling that phrase and see if it matches your intentions. If it > does, and you are concerned with speed, a 100-element dictionary > mapping each byte-pair to a packed byte might be a good idea instead > of the bit bashing: > convert = { > '78': '\x78', > ... > } > See http://mail.python.org/pipermail/python-list/2000-October/056329.html > > HTH, > John > -- http://mail.python.org/mailman/listinfo/python-list
