On Nov 26, 9:42 am, Kelie <[EMAIL PROTECTED]> wrote:
> Hello,
>
> This function does I what I want. But I'm wondering if there is an
> easier/better way. To be honest, I don't have a good understanding of
> what "pythonic" means yet.
>
> def divide_list(lst, n):
> """Divide a list into a number of lists, each with n items. Extra
> items are
> ignored, if any."""
> cnt = len(lst) / n
> rv = [[None for i in range(n)] for i in range(cnt)]
> for i in range(cnt):
> for j in range(n):
> rv[i][j] = lst[i * n + j]
> return rv
>
> Thanks!
x = ['1', '2', '3', '4', '5', '6', '7', '8']
def divide_list(lst, n):
rv = []
for i in range(int(round((len(lst)/n),0))):
rv.append(lst[i*n:(i+1)*n])
return rv
tmp = divide_list(x, 3)
tmp
[['1', '2', '3'], ['4', '5', '6']]
One way to do it.
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