On Nov 23, 2007 1:29 AM, Roc Zhou <[EMAIL PROTECTED]> wrote: > Hello, > > I'm now being confused by this segment of code: > >>> class Test: > ... var = 1 > ... def func(self): pass > ... > >>> x = Test() > >>> y = Test() > >>> x.var is y.var > True > >>> x.func is y.func > False > >>> id(x.var); id(y.var) > 146132400 > 146132400 > >>> id(x.func); id(y.func) > -1208243388 > -1208243388 > > Since both "var" and "func" are the variable of the class object, and
"members", not variables. > x.var is y.var, why x.func is not y.func while their id() return the > same value. > It's because of the descriptor lookup that turns functions into methods. If you just print x.func and y.func on the console you'll see that they're bound methods of a specific instance - not the unbound method object you'd see if you look at Test.func. Your id test is giving you misleading results because you aren't storing the boundmethod between lookups - the objects have the same id not because they are the same object, but because they're created one after the other and are re-using the same memory block. -- http://mail.python.org/mailman/listinfo/python-list
