> Thanks those answers make sense. But for this function if defined > outside the class: > > >> def pre(fn): >> def new_func(*args, **kwargs): >> print "'hi'" >> fn(*args, **kwargs) >> return new_func >> > > Can new_func reference self? Would self just be one of the args? > Hi,
new_func is a dynamically created function. When pre() is called, it will return this new function. (This happens when Python tries to excute the "class A(object)" statement, in other words: it happens during class definition.) The returned function is unound, and it assigned to A.func. In other words, the function object is returned by pre(), but is not called. "new_func" will only be called when you call a.func in your example. When that happens, Python will find that that object 'a' has no direct attribute called "func", but there is one in its class "A". So it will call A.func as a bound method, with its "self" parameter set to the object that was used to call the method -- namely, "a". Hope this helps. Laszlo -- http://mail.python.org/mailman/listinfo/python-list
