> I am looking for a way to determine the order of keyword parameters
> passed on to a class method.
I'm fairly certain it's not possible, as how would code like this
behave:
def my_func(**kwd):
kwd = OrderedDict(kwd) #magic happens here?
return do_something(kwd)
my_dict = {'hello':42, 'world':3.14159}
print my_func(**my_dict)
This is regularly used in lots of code. The ordering of the
contents of my_dict is already lost before the my_func() ever
gets a chance to see it. And in case one suggests trying to
sniff the source-code for the ordering, it's easy to break with
things like
my_dict = read_dict_from_file(get_filename_from_user())
where the dict and its source are completely outside the scope of
the code.
The only way around it I see is to force the user to pass in an
ordered dict explicitly:
def my_func(ordered_dict_of_kwdargs):
return do_something(ordered_dict_of_kwdargs)
my_dict = OrderedDict()
my_dict['hello'] = 42
my_dict['world'] = 3.14159
print my_func(my_dict)
-tkc
--
http://mail.python.org/mailman/listinfo/python-list
