[EMAIL PROTECTED] wrote:
> from numpy import *
>
> a = zeros((2,40), int)
>
> fields = {}
> field = 10
> fields[field] = '30A', 5
>
> iy = int(fields[field][1])
> ix = int(fields[field][0].rstrip('AB'))
>
> for i in range(2):
> for j in range(iy):
> # put(a,[39 - j],[1]) #1d
>
> Can someone help me figure out how I would do it for multiple rows?
numpy questions are best asked on the numpy mailing list.
http://www.scipy.org/Mailing_Lists
> I thought,
>
> put(a,[i][39-j],[1])
>
> but,
>
> Traceback (most recent call last):
> put(a,[i][39 - j],[1])
> IndexError: list index out of range
In this case, you don't really want put(). Just use indexing:
for i in range(2):
for j in range(iy):
a[i,39-j] = 1
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless enigma
that is made terrible by our own mad attempt to interpret it as though it had
an underlying truth."
-- Umberto Eco
--
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