On Sat, 10 Nov 2007 09:02:01 -0800, Mike Howarth wrote: > Hi > > Seem to be having a bit of brainfreeze this evening. > > Basically I'm reducing an array of prices like so: >>> subtotal = reduce(operator.add, itemprices) > > This gives me a string of '86.00.00' which I am trying to use with > decimal objects. Python 2.4 is not particularly happy with this.
Let me guess... your test data is: itemprices = ['86.0', '0.00'] What happens if you use test data like this? itemprices = ['86.0', '0.00', '1.99', '12.03'] The first problem that you have is that your prices are strings. Is that deliberate? This is not necessarily a fault. Your second problem is that the + operator concatenates strings, not adds them. "1.0" + "2.0" = "1.02.0", not "3.0". This, on the other hand, is absolutely a fault. Your code is producing invalid data. > Additionally I can't simply convert the string to a decimal as it would > be invalid given it has multiple decimal points. Yes. Rather than trying to fix the invalid data after it is produced, you should fix your code so it doesn't produce the wrong answer in the first place. > Being relatively new to python, I'm not sure how I could round the > string or similar. Anyone got any ideas? This is NOT the answer you NEED, but this is the answer you ask for. To cut out the extra decimal places, use this: >>> subtotal = '86.00.00' >>> subtotal[:-3] '86.00' Now that I've told you how to do it, let me re-iterate that you shouldn't do it. Your problem isn't that your result has an extra ".00" at the end of the result. Your problem is that your result is WRONG. Fix the result in the first place. I'd be looking at something like this: # start with a list of strings itemprices = ['86.0', '0.00', '1.99', '12.03'] # convert them into decimal objects itemprices = map(decimal.Decimal, itemprices) # and add them subtotal = sum(itemprices) -- Steven. -- http://mail.python.org/mailman/listinfo/python-list
