Hi,
if I use part.get_filename() with the following email part:
------_=_NextPart_001_01C81B11.52AB8006
Content-Type: application/vnd.ms-excel;
name="=?iso-8859-1?Q?30102007=28aktualisiert=29=5FK=FCndigungen_enviaM=5FErdgas?=
=?iso-8859-1?Q?_S=FCds__GmbH=2Exls?="
Content-Disposition: attachment;
filename="=?iso-8859-1?Q?30102007=28aktualisiert=29=5FK=FCndigungen_enviaM=5FErdgas?=
=?iso-8859-1?Q?_S=FCds__GmbH=2Exls?="
Content-Description:
=?iso-8859-1?Q?30102007=28aktualisiert=29=5FK=FCndigungen_enviaM=5FErdgas?=
=?iso-8859-1?Q?_S=FCds__GmbH=2Exls?=
Content-Transfer-Encoding: base64
0M8R4KGxGu...
I get a filename which includes a newline character and the ?iso... encoding
is not resolved. But the mail user agent "mutt" does display the filename
correct. I tried it with the latest email packages (4.0.2).
Any hints how to parse this filename?
Thomas
--
http://mail.python.org/mailman/listinfo/python-list
