Falcolas a écrit :
> Please help me understand the mechanics of the following behavior.
>
>
>>>>def d():
>
> header = 'I am in front of '
> def e(something):
> print header + something
> return e
>
>
>>>>f = d()
>>>>f('this')
>
> I am in front of this
>
>>>>del(d)
>>>>f('this')
>
> I am in front of this
>
> The way I understand it, function d is an object,
Right.
> as is e.
Right.
> However I
> don't quite grok the exact relationship between e and d.
>
> Is e
> considered to be a subclass of 'd',
Nope.
> so that it has access to it's
> parent's __dict__ object, in order to access the value of 'header'? Or
> is this persistence managed in a different fashion?
As Diez said, it's called a lexical closure. A lexical closure is a
function that captures and carries the lexical scope it was defined in
with it - it 'closes over' it's environnement. Each time you call d, it
returns a new function object (using the same code object) with a
different environnement. You'll find this environement in f.func_closure.
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