On Sat, 03 Nov 2007 07:18:17 +0000, Sullivan WxPyQtKinter wrote: > def f(): > print x > x=0 > > x=12345 > f() > > result is: > Traceback (most recent call last): > File "...\test.py", line 5, in ? > f() > File "...\test.py", line 2, in f > print x > UnboundLocalError: local variable 'x' referenced before assignment
When Python compiles your function f(), it sees that you have assigned to x, and that there is no line "global x", so it knows that x is a local variable. But when you call f(), you try to print x before the local x has a value assigned to it. Hence the (accurate but hardly user-friendly) error message. You can also do this: >>> help(UnboundLocalError) Help on class UnboundLocalError in module exceptions: class UnboundLocalError(NameError) | Local name referenced but not bound to a value. As far as I know, there is no way to read the value of global x if and only if local x doesn't exist. -- Steven -- http://mail.python.org/mailman/listinfo/python-list
