Marc 'BlackJack' Rintsch>``s.startswith('E')`` is a little safer than
``s[0] == 'E'`` as the former returns `False` if `s` is empty while
the latter raises an `IndexError`.<
Thank you.
In this problem if there is an empty key in the record dict then maybe
it's better to raise an IndexError, because probably that's not a
normal condition. Sometimes less safe is more safe :-)
With few tests I have seen that (using Psyco) this is probably the
faster solution (and it's quite readable by a newbe too):
record2 = {}
for k in record:
if k[0] == 'E':
record2[k] = record[k]
Misteriously with Psyco it becomes faster than even the equivalent D
language solution (keys starting with "E" are about 5% of the total)
that is statically typed and generally very fast:
string[string] record2;
foreach(k, v; record)
if (k[0] == 'E')
record2[k] = v;
Bye,
bearophile
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