On Oct 19, 1:44 am, MRAB <[EMAIL PROTECTED]> wrote: > On Oct 18, 7:05 am, Michele Simionato <[EMAIL PROTECTED]> > wrote:> On Oct 17, 5:58 pm, Ixiaus <[EMAIL PROTECTED]> wrote: > > > > def bin2dec(val): > > > li = list(val) > > > li.reverse() > > > res = [int(li[x])*2**x for x in range(len(li))] > > > print sum(res) > > > > It basically does the same thing int(string, 2) does. > > > > Thank you for the responses! > > > BTW, here is the reverse function dec2bin, so that you can > > bang your head on it for a while ;) > > It returns '' when number == 0, so you need to test for that case: > > > def baseN(number, N=2): > > """ > > >>> baseN(9, 2) > > '1001' > > """ > > assert 2 <= N <= 10 > > assert isinstance(number, int) and number >= 0 > > if number == 0: > return "0" >
Hey, Isn't if not number: return "0" faster? -- http://mail.python.org/mailman/listinfo/python-list
