Marc 'BlackJack' Rintsch wrote: > On Tue, 16 Oct 2007 06:18:51 +0000, Tim Roberts wrote: > > > John Machin <[EMAIL PROTECTED]> wrote: > >>On Oct 15, 4:02 am, Abandoned <[EMAIL PROTECTED]> wrote: > >>> Hi.. > >>> I have a list as a=[1, 2, 3 .... ] (4 million elements) > >>> and > >>> b=",".join(a) > >>> than > >>> TypeError: sequence item 0: expected string, int found > >>> I want to change list to a=['1','2','3'] but i don't want to use FOR > >>> because my list very very big. > >> > >>What is your worry: memory or time? The result string will be very > >>very very big. > > > > It's an interesting mental exercise to try to figure out just how large > > that string will be, without using Python. > > > > I get 30,888,889 bytes... > > I think you have an off by one error here. (One number, not one byte) :-)
It's certainly off : [Best viewed in a fixed-width font ... umm, do they still sell squared paper for doing arithmetic on? I had to rip a page out of a notebook and rotate it through 90 degrees] 3000001 x 8 = 24000008 0900000 x 7 = 06300000 0090000 x 6 = 00540000 0009000 x 5 = 00045000 0000900 x 4 = 00003600 0000090 x 3 = 00000270 0000009 x 2 = 00000018 ------- -------- 4000000 30888896 less one for a comma counted above but not used -> 30888895 difference is 6 bytes which is one number (8) LESS 2 bytes Cheers, John -- http://mail.python.org/mailman/listinfo/python-list
