On Wed, 10 Oct 2007 20:25:00 +0000, Paul Hankin wrote: >> A "works-for-me": >> >> >>> pairs = (test[i:i+2] for i in xrange(len(test)-1)) >> >>> for a,b in pairs: >> ... print a,b > > for a, b in zip(test, test[1:]): > print a, b
May be unfortunately slow if test is half a gigabyte of data, what with essentially making three copies of it. Lazy procedures like the generator expression above are often much better. Just for completion, here's another way: prev = test[0] for i in xrange(1, len(test)): print prev, test[i] prev = test[i] -- Steven. -- http://mail.python.org/mailman/listinfo/python-list