On Oct 10, 4:05 pm, John Machin <[EMAIL PROTECTED]> wrote:
> On 10/10/2007 8:19 PM, Shriphani wrote:
>
>
>
> > Hello all,
>
> > Let us say I have a function like this:
>
> > def efficientFiller(file):
> > worthless_list = []
> > pot_file = open(file,'r')
> > pot_file_text = pot_file.readlines()
> > for line in pot_file_text:
> > if line.find("msgid") != -1:
> > message_id = shlex.split(line)[1]
> > if message_id in dictionary:
> > number = pot_file_text.index(line)
> > corresponding_crap =
> > dictionary.get(message_id)
> > final_string = 'msgstr' + " " + '"' +
> > corresponding_crap + '"' + '\n'
> > pot_file_text[number+1] = final_string
> > yield pot_file_text
>
> > efficient_filler = efficientFiller("libexo-0.3.pot")
> > new_list = list(efficient_filler)
> > print new_list
>
> > I want to plainly get the last value the yield statement generates.
> > How can I go about doing this please?
>
> I don't think that 'efficient' and 'plainly' mean what you think they
> mean. However to answer your question:
>
> new_list[-1] if new_list else None
>
> BTW I get the impression that the yield statement yields the whole
> pot_file_text list each time, so that new_list will be a list of lists;
> is that intentional?
Hello again,
I am sorry for having made that extra post and should have seen that
the solution I wanted was posted here. Anyway thanks a lot
Regards,
Shriphani Palakodety
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