In message <[EMAIL PROTECTED]>, Neil Cerutti wrote:
> On 2007-10-03, Lawrence D'Oliveiro <[EMAIL PROTECTED]>
> wrote:
>> In message <[EMAIL PROTECTED]>, Ben Finney wrote:
>>
>>> Lawrence D'Oliveiro <[EMAIL PROTECTED]> writes:
>>>
>>>> On my Gentoo system:
>>>>
>>>> >>> import os
>>>> >>> os.path
>>>> <module 'posixpath' from '/usr/lib64/python2.5/posixpath.pyc'>
>>>>
>>>> It's just a variable that happens to point to the posixpath module.
>>>
>>> There's no "pointing" going on. It's another name bound to the
>>> same object, of equal status to the 'posixpath' name.
>>>
>>> Python doesn't have pointers, and even "variable" is a
>>> misleading term in Python. Best to stick to "name" and "bound
>>> to".
>>
>> In Python, all names _are_ variables. They are not "bound" to
>> objects. The value of os.path is a pointer. It's implemented as
>> a pointer, it has all the semantics of a pointer.
>
> No. A pointer is also an iterator.
>
> void duplicate(char *d, const char *s)
> {
> while (*d++ = *s++)
> ;
> }
So if you can't do pointer arithmetic, then it's not a pointer? Trying this:
void duplicate(void *d, const void *s)
{
while (*d++ = *s++)
;
}
I get:
test.c: In function 'duplicate':
test.c:3: warning: dereferencing 'void *' pointer
test.c:3: warning: dereferencing 'void *' pointer
test.c:3: error: invalid use of void expression
So you can't do arithmetic or iterate with a void * pointer. Does that mean
it's not really a pointer?
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