>> in python2.4, i read lines from a file with >> >> for lineNum, line in enumerate(f): ... >> >> However, lineNum soon overflows and starts counting backwards. How do >> i force enumerate to return long integer? > > Most probably you can't, because it is a C-written function I presume. > > But as python 2.4 has generators, it's ease to create an enumerate yourself: > > > def lenumerate(f): > i = 0 > for line in f: > yield i, line > i += 1
I'd consider this a bug: either in the implementation of enumerate(), or in the documentation http://docs.python.org/lib/built-in-funcs.html#l2h-24 which fails to mention such arbitrary limitations. The documentation describes what you create as an lenumerate() function. Most likely, if one doesn't want to change the implementation, one should update the documentation for enumerate() to include a caveat like xrange() has http://docs.python.org/lib/built-in-funcs.html#l2h-80 """ Note: xrange() is intended to be simple and fast. Implementations may impose restrictions to achieve this. The C implementation of Python restricts all arguments to native C longs ("short" Python integers), and also requires that the number of elements fit in a native C long. """ While yes, it's easy enough to create the above lenumerate generator (just as it's only slightly more work to create an lxrange function), it would be good if the docs let you know that you might need to create such a function -tkc -- http://mail.python.org/mailman/listinfo/python-list
