En Sat, 29 Sep 2007 17:32:15 -0300, marvinla <[EMAIL PROTECTED]> escribi�:
> Have you tried a del? > >>> import socket >>> dir() > ['__builtins__', '__doc__', '__name__', 'socket'] >>> del socket >>> dir() > ['__builtins__', '__doc__', '__name__'] py> import socket py> del socket py> import sys py> sys.modules['socket'] <module 'socket' from 'c:\apps\Python25\lib\socket.pyc'> del only removes the reference from the current namespace, but the module is still loaded and available. del sys.modules['socket'] would remove the module so the next import statement will have to reload it. Back to the original question, timeoutsocket replaces some objects in the socket module with its own versions, just "unloading" timeoutsocket would not be enough, the changes had to be reverted. timeoutsocket is an old hack for Python 2.2 and earlier. Since 2.3 you can achieve the same thing using socket.setdefaulttimeout() so unless you are forced to use such ancient versions, it can be dropped. -- Gabriel Genellina -- http://mail.python.org/mailman/listinfo/python-list
