Casey <[EMAIL PROTECTED]> wrote:
> I would recommend the OP try this:
>
> run the (I)python shell and try the following:
>
>>>> a = [x for x in "abcdefg"]
>>>> a
> ['a','b','c','d','e','f','g']
>>>> "c" in a
> True
>>>> "c" in a == True
> False
>>>> ("c" in a) == True
> True
>
> The reason your conditional failed is that it was interpreted as "c"
> in (a == True) which is False.
That was my first thought, too. But watch:
>>> a = list("abcde")
>>> a
['a', 'b', 'c', 'd', 'e']
>>> "c" in (a == True)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: argument of type 'bool' is not iterable
Then it dawned on me (is this the right phrase?): It's the same situation
as e.g. x < y >= 1, which means the same as "x < y and y >= 1" (except
that y is only evaluated once). So '"c" in a == True' gets evaluated as
'"c" in a and a == True'.
> the "==" operator binds at a higher precedence level than the "in"
> operator, just as multiplication binds higher than addition
Operator precedence plays no role in this case. It is a case of
'chained' comparisons.
Hope that clears it up
Marc
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