Dnia Mon, 24 Sep 2007 10:41:22 -0300, Ricardo Aráoz napisał(a):
> Would this work for you?
Thank you both for help. Well - yes and no :). It's getting more
interesting:
First, your code:
class myrow():
def __init__(self, idict = {}):
self.container = idict
def __str__ (self):
return self.container.__str__()
results = [
{'a': 12, 'b' :30 },
{'a': 13, 'b' :40 }
]
mystruct = []
for row in results:
mystruct.append(myrow(row))
results[1]['b'] = 444
print results # [{'a': 12, 'b': 30}, {'a': 13, 'b': 444}]
print mystruct # does not work ok , you should probably define
# mystruct's __str__ method properly
# But, save for the __str__ thingy, the rest is ok.
for row in mystruct:
print row
# {'a': 12, 'b': 30}
# {'a': 13, 'b': 444}
And now let's try to swap results with something else:
print id(results)
# new resultset
results = [
{'a': 112, 'b' : 130 },
{'a': 113, 'b' : 140 }
]
print id(results)
for row in mystruct:
print row
# {'a': 12, 'b': 30}
# {'a': 13, 'b': 444}
At first glance (before adding id()) it's a little bit weird. The original
object was supposedly "overwritten", but as one can see it has different
id then the new one. mystruct still holds references to old object,
though. I can handle it and just change original object, but I'm curious
if there's a way to "swap" them "on-the-fly".
Thanks one again.
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