HYRY wrote: > This works, but I think the key of DOC is too long, so I want to use > the id of list.append.__doc__ as the key; or use the id of > list.append: > > DOC[id(list.append.__doc__)] = "..." > DOC[id(list.append)] = "..." > > So, I asked how to get list.append from a.append, and why > id(list.append.__doc__) changes.
dictionaries hold *references* to objects, not copies of the object values, so that won't save you anything. </F> -- http://mail.python.org/mailman/listinfo/python-list
