On 9/24/07, Robert Dailey <[EMAIL PROTECTED]> wrote: > Hi, > > I'm attempting to create a regular expression that removes redundancy in > empty XML elements. For example: > > <root></root> > > The regular expression would convert the XML above into: > > <root/>
If you can guarantee that the XML is well-formed, then this should work: pattern = r'<([^/>][^>]*(?<!/))></[^>]+>' replace = r'<\1/>' -Miles -- http://mail.python.org/mailman/listinfo/python-list
