Dmitri Fedoruk wrote:
> def extApplyXslt(xslt, data, logger ):
> try:
> strXslt = urllib2.urlopen(xslt).read()
> # i have to read the xslt url to the python string
> except urllib2.HTTPError, e:
> .......
> except urllib2.URLError, e:
> .............
> try:
> xslt_parser = etree.XMLParser()
> xslt_parser.resolvers.add( PrefixResolver("XSLT") )
>
> # and now I have to use the string; a more elegant solution,
> anyone?
Sure, lxml.etree can parse from file-like objects. Just hand in the result of
urlopen().
Apart from that, I saw that you found your way to the lxml mailing list, I'll
respond over there.
Stefan
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