On Sat, 01 Sep 2007 13:37:29 -0600, Michael L Torrie wrote:
> What's wrong, then, with doing:
>
> if i in list:
> print list.index(i)
If `i` is in the list this does the linear lookup twice.
> If we were to program this .index() method in some language that
> enforces contracts, like haskell, then we'd say that .index() expects a
> value that exists in the list. So if you violate the contract, why
> should you expect to *not* get an exception. Doing it any other way,
> though, makes the code a lot more error prone.
Does Haskell exceptions? In Haskell I would expect such a function to
return the `Maybe` type.
Ciao,
Marc 'BlackJack' Rintsch
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