Well, I know it's quite ugly what I did to the code, but any
improvements are welcome.
Actually, it doesn't work as it should yet.
The items should stay the same as at the beginning.
I say in one sentence what I want to achieve:
Synchronized items with dblist.
It should remove hosts from items which are not dblist
or it should add a new host from dblist which is not in items.
I'm sorry I'm not very skilled programmer.
What O notations(algorithm complexity) I introduced to it?
I know made it much slower this way.
dblist = [{'id':1, 'host':'google.com','ip_address':'1.2.3.4'},
{'id':3, 'host':'msn.com','ip_address':'11.3.2.3'},
{'id':9, 'host':'yahoo.com','ip_address':'5.6.7.8'}]
class Item(object):
def __init__(self, id, host, **discarded):
self._tuple = (id, host)
def __hash__(self):
return hash(self._tuple)
def __eq__(self, other):
return self._tuple == other._tuple
def __repr__(self):
return "Item(id=%r, host=%r)" % self._tuple
def syncMemAndDBlist_1():
for d in dblist:
item = Item(**d)
if item not in items:
print "adding", item
items.add(item)
else:
print item, "already there"
def syncMemAndDBlist_2(a):
while a > 0:
for i in items:
if i not in dblistitems:
items.remove(i)
break
a -= 1
if len(items) == 0:
syncMemAndDBlist_1()
items = set([Item(1, "google.com"), Item(3, "yahoo.com"), Item(9,
"msn.com")])
dblistitems = set()
for d in dblist:
dblistitems.add(Item(**d))
a = len(items)
b = len(dblistitems)
if a < b:
syncMemAndDBlist_1()
else:
syncMemAndDBlist_2(a)
print 'final items are' ,items
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