Hi,
Using finditer in re module might help. I'm not sure it is lazy nor
performant. Here's an example :
=== BEGIN SNAP
import re
reLn = re.compile(r"""[^\n]*(\n|$)""")
sStr = \
"""
This is a test string.
It is supposed to be big.
Oh well.
"""
for oMatch in reLn.finditer(sStr):
print oMatch.group()
=== END SNAP
Regards,
Francis Girard
Le vendredi 25 Février 2005 16:55, Jeremy Sanders a écrit :
> I have a large string containing lines of text separated by '\n'. I'm
> currently using text.splitlines(True) to break the text into lines, and
> I'm iterating over the resulting list.
>
> This is very slow (when using 400000 lines!). Other than dumping the
> string to a file, and reading it back using the file iterator, is there a
> way to quickly iterate over the lines?
>
> I tried using newpos=text.find('\n', pos), and returning the chopped text
> text[pos:newpos+1], but this is much slower than splitlines.
>
> Any ideas?
>
> Thanks
>
> Jeremy
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