On Aug 20, 3:15 pm, John Machin <[EMAIL PROTECTED]> wrote: > On Aug 20, 9:52 pm, [EMAIL PROTECTED] wrote: > > > Hi I have a time in microseconds, for example 0x8C905CBA7F84AF4. I > > want this to a normal view in hh:mm:ss DD:MM:YYYY. I tried with > > datetime, but it only takes a max of 1000000 microseconds is there > > another solution? > > Your question can be interpreted in two possible ways: > > 1. You have an interval or duration (independent of a calendar point) > and you want to express it in years, months, days, hours, etc. This is > not possible, due to the variable number of days in a month. The best > that you can do is express it as days, hours, etc. > > >>> microsecs = 0x8C905CBA7F84AF4 > >>> secs = microsecs // 1000000 # or round to nearest if you prefer > >>> mins, secs = divmod(secs, 60) > >>> hrs, mins = divmod(mins, 60) > >>> days, hrs = divmod(hrs, 24) > >>> days, hrs, mins, secs > > (7326893L, 11L, 1L, 16L) > > > > 2. You want to know the (Gregorian) calendar point that is > 0x8C905CBA7F84AF4 microseconds after some epoch. In this case you need > to specify what the epoch is. Then you can try something like: > > >>> datetime.datetime.fromordinal(1) + > >>> datetime.timedelta(microseconds=microsecs > > ) > Traceback (most recent call last): > File "<stdin>", line 1, in <module> > OverflowError: date value out of range > > >>> # Whoops! > >>> years_approx = days / 365.25 > >>> years_approx > 20059.939767282682 > > Hmmm, one of us seems to be missing something ...
Sorry, sorry, sorry it was the wrong value, it should be 0xE0E6FAC3FF3AB2. -- http://mail.python.org/mailman/listinfo/python-list
