No - that doesn't work, im_class gives me the current class - in the case of inheritance, I'd like to get the super class which provides 'bar'.
I suppose I could walk the __bases__ to find the method using the search routine outlined in: http://www.python.org/2.2/descrintro.html but I was hoping for an automatic way of resolving this. vic On Fri, 25 Feb 2005 14:54:34 +0000, Richie Hindle <[EMAIL PROTECTED]> wrote: > > [vic] > > I'm doing some evil things in Python and I would find it useful to > > determine which class a method is bound to when I'm given a method > > pointer. > > Here you go: > > >>> class Foo: > ... def bar(self): > ... pass > ... > >>> Foo.bar.im_class > <class __main__.Foo at 0x008ED720> > >>> Foo().bar.im_class > <class __main__.Foo at 0x008ED720> > >>> > > -- > Richie Hindle > [EMAIL PROTECTED] > > -- > http://mail.python.org/mailman/listinfo/python-list > -- http://mail.python.org/mailman/listinfo/python-list
