I would start with something like this:
somestring = '/foo/bar/beer/sex/cigarettes/drugs/alcohol/'
somelist = somestring.split('/')
print somelist
This is close to what you seem to want. Good luck.
*gina*
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Friday, February 25, 2005 8:36 AM
To: python-list@python.org
Subject: split a directory string into a list
QUESTION:
How do I split a directory string into a list in Python, eg.
'/foo/bar/beer/sex/cigarettes/drugs/alcohol/'
becomes
['foo','bar','beer','sex','cigarettes','drugs','alcohol']
I was looking at the os.path.split command, but it only seems to
separate the filename from the path (or am I just using it wrong?). I
don't want to do it manually if I can help it, as there will have to be
exceptions for the cases where there is (not) a trailing (leading)
slash, or escape sequences involving /. Is there a built in command for
this?
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