On Mon, 06 Aug 2007 11:13:45 +0000, Alex Popescu wrote: > Stargaming <[EMAIL PROTECTED]> wrote in news:46b6df49$0$26165 > [EMAIL PROTECTED]: > [snip] >> >> You're just unluckily shadowing the name `y` in the local scope of > your >> function. Your code snippet could be rewritten as:: >> >> def f(x, y=None): >> if y is None: my_y = [] >> else: my_y = y >> my_y.append(x) >> return my_y >> >> HTH, >> Stargaming > > For the given example this will continue to print: > >> print f(23) # prints [23] >> print f(42) # prints [42] > > so this doesn't solve/explain OP's initial question. A previous post has > already clarified the reasons for seeing this normal behavior. > > bests, > ./alex
If it keeps normal behaviour, that's exactly what it ought to explain. In his local scope, there is an `y`, having the value of f.func_defaults. Because it's harder to see "hey, in some cases, y vanishes, in some it survives", I invented the new local reference `my_y` -- which should be clear to go away after completion of the function body. Regards, Stargaming -- http://mail.python.org/mailman/listinfo/python-list
