Steven D'Aprano wrote:
> On Fri, 03 Aug 2007 17:22:40 -0700, James Stroud wrote:
>
>
>>Basically, what I am trying to acomplish is to be able to do this in any
>>arbitrary module or __main__:
>>
>>
>>funcname = determined_externally()
>>ModuleUser.do_something_with(AModule, funcname)
>>
>>
>>Ideally, it would be nice to leave out AModule if the functions were
>>designed in the same namespace in which do_something_with is called.
>
>
> I second Carsten Haese's suggestion that instead of passing function
> names, you pass function objects, in which case you don't need the module.
> But perhaps you need some way of finding the function, given its name.
>
> def get_function_from_name(name, module=None):
> if module is None:
> # use the current namespace
> namespace = locals() # or globals() if you prefer
> else:
> namespace = module.__dict__
> return namespace[name]
>
>
This assumes that get_function_from_name is defined in the same module
as the function named by name. However, I want this:
Module Behavior
============== ====================================================
UserDefined1 Imports FunctionUser
ThirdParty Contains User Functions (May be ==UserDefined1)
FunctionUser do_something_with() and/or get_function_from_name()
So the name-to-function mapping is done in FunctionUser but the function
is actually defined in UserDefined1 (or ThirdParty if ThirdParty is
different than UserDefined1).
James
--
James Stroud
UCLA-DOE Institute for Genomics and Proteomics
Box 951570
Los Angeles, CA 90095
http://www.jamesstroud.com/
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