greg <[EMAIL PROTECTED]> writes:

> Be careful with this. If you have two values that are
> very close together, but on different sides of a rounding
> boundary, they will end up as distinct keys even though
> they "should" be regarded as equal.

I don't think this is a big problem. It will only give me one more
node. 

Wouldn't the same be possible if I use bisect?

-- 
Brian (remove the sport for mail)
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