James Stroud wrote: > py> f = lambda n, r=None: f(n/26, (r if r else [])) + [n%26] if n/26 > else [n%26] > py> f(300000) > [17, 1, 20, 12] > py> f(30000) > [1, 18, 9, 22] > py> f(3000) > [4, 11, 10] > py> f(1000) > [1, 12, 12] > >
Oops, those are backwards. Should be: f = lambda n, r=None: [n%26] + f(n/26, (r if r else [])) if n/26 else [n%26] -- James Stroud UCLA-DOE Institute for Genomics and Proteomics Box 951570 Los Angeles, CA 90095 http://www.jamesstroud.com/ -- http://mail.python.org/mailman/listinfo/python-list
