On Wed, 25 Jul 2007 15:46:58 +0000, beginner wrote: > On Jul 25, 10:19 am, Stargaming <[EMAIL PROTECTED]> wrote: >> On Wed, 25 Jul 2007 14:50:18 +0000, beginner wrote: [snip] >> >> > Another question is how do I pass a tuple or list of all the >> > aurgements of a function to the function. For example, I have all the >> > arguments of a function in a tuple a=(1,2,3). Then I want to pass >> > each item in the tuple to a function f so that I make a function call >> > f(1,2,3). In perl it is a given, but in python, I haven't figured out >> > a way to do it. (Maybe apply? but it is deprecated?) >> >>> def foo(a, b, c): print a, b, c >> ... >> >>> t = (1, 2, 3) >> >>> foo(*t) >> >> 1 2 3 >> >> Have a look at the official tutorial, 4.7.4http://www.python.org/doc/ >> current/tut/node6.html#SECTION006740000000000000000 >> >> > Thanks, >> > cg >> >> HTH, >> Stargaming > > Hi Stargaming, > > I know the * operator. However, a 'partial unpack' does not seem to > work. > > def g(): > return (1,2) > > def f(a,b,c): > return a+b+c > > f(*g(),10) will return an error.
http://docs.python.org/ref/calls.html > Do you know how to get that to work? Well, there are several ways to solve this. You could either invoke f(*g () + (10,)). Might be a bit nasty and unreadable, though. Or you could just change your function f to accept them in reversed order (f(10, *g) should work) or convert g() to return a dictionary like {'b': 1, 'c': 2} and use f(10, **g). But if your function f's hugest use case is being called with g(), changing f to accept something and g's result (tuple) -- unpacking it inside f -- might be better. -- http://mail.python.org/mailman/listinfo/python-list
