On Fri, 2007-07-13 at 19:22 +0000, Robert Dailey wrote: > Correction: > > I ran a few more tests and python actually does a pass by value, > meaning that a "copy" is made
That is patently incorrect. A function call in Python *never* makes a copy of any of its arguments. > and the external variable that was > passed in remains unchanged. That depends entirely on what kind of object the "variable" is and how you're trying to change the "variable." > I actually want to know how to "pass by > reference", in that any changes made to a parameter inside of a > function also changes the variable passed in. Python is Pass By Reference. Always. Period. The root of your misunderstanding is that you don't understand how the assignment statement works in Python. You come from the world of C where a variable is a predefined memory location and "a=1;" means "Write the value '1' into the memory location that is inhabited by 'a', obliterating any contents that were previously in this memory location." Python doesn't actually have variables. Python has objects and namespaces, and assignment statements work very differently. This has been widely discussed before. For more information, see http://effbot.org/zone/python-objects.htm and the thread "Understanding python functions" that started just yesterday on this very same list. HTH, -- Carsten Haese http://informixdb.sourceforge.net -- http://mail.python.org/mailman/listinfo/python-list
