On Mon, 09 Jul 2007 19:57:14 +0000, ChrisEdgemon wrote: > I've got a set with contents like: [filename1.mp3, filename2.mp3, > filename3.mp3, ...] > I've got another set with contents like [filename1.ogg, > filename3.ogg, ...] > And another set with contents like [filename1, filename 2, ...] > > I'd like to be able to compare set 1 with set 2 and have it match > filename1 and filename3, or compare set 1 with 3 and get back > filename1, filename2. etc. > > Is there a way for me to do this inside the compare function, rather > than having to make duplicate copies of each set?
What compare function are you talking about? Unless you have truly astronomical numbers of unique filenames (and remember that what's big to you is probably not big to Python), the easiest way is to make a copy of each set with the file extensions stripped off the file names. Use os.path.splitext() for that. -- Steven. -- http://mail.python.org/mailman/listinfo/python-list
