Paul McGuire <[EMAIL PROTECTED]> writes: >> >>> False in [3, 2, 1, 0, -1] >> >> True # no False here>>> all([3, 2, 1, 0, -1]) >> >> False # false value present, not necessarily False > > I think if you want identity testing, you'll need to code your own;
I'm aware of that, I simply pointed out that "False in list" and any(list) are not equivalent and where the difference lies. >>>> any(map(lambda _ : _ is False,[3,2,1,0,-1])) Note that you can use itertools.imap to avoid the unnecessary intermediate list creation. Even better is to use a generator expression: >>> any(x is False for x in [3, 2, 1, 0, -1]) False >>> any(x is False for x in [3, 2, 1, 0, -1, False]) True -- http://mail.python.org/mailman/listinfo/python-list
