On Jul 6, 12:21 am, Christoph Zwerschke <[EMAIL PROTECTED]> wrote: > Kay Schluehr wrote: > > If you are sure that the exception isn't caught on another level just > > use the following showtraceback() function, manipulate it's output > > slightly and terminate your program with sys.exit() > > That's what I want to avoid. In my case the error is displayed and > evaluated in a completly different piece of software. > > -- Chris
Probably the simplest solution would be to create a new exception and wrapping the old one and the additional info. Unfortunately, this may have a huge impact on 3rd party code that was catching the original exception. So, I think you should create an utility factory-like function that is either creating a new exception instance as the one caught and with the additional information, or an utility that knows how to modify the caught exception according to its type. In the first case you will need somehow to tell to the new instance exception the real stack trace, because by simply raising a new one the original stack trace may get lost. bests, ./alex -- .w( the_mindstorm )p. -- http://mail.python.org/mailman/listinfo/python-list