"markscottwright" <[EMAIL PROTECTED]> writes:
> But when I try to do it iteratively, it just hangs when I try to
> evaluate the results (for count > 1):
>
> def repeated2(f, count):
> newfun = f
> for i in range(count-1):
> newfun = lambda x: newfun(f(x))
> return newfun
>
> For the life of me, I can't figure out why. It seems like for count =
> 2, for example, the results from repeated2 should be lambda x: f(f(x)),
> but it doesn't seem to be.
It's Python's scoping madness. Try:
def repeated2(f, count):
newfun = lambda x: x # identity
for i in range(count):
newfun = lambda x, g=newfun: g(f(x))
return newfun
--
http://mail.python.org/mailman/listinfo/python-list
