I need to convert a generator expression to a list expression so it will work under python 2.3.
I rewrote this:
for c in range(128): even_odd = (sum(bool(c & 1<<b) for b in range(8))) & 1
As this:
for c in range(128): bo = [bool(c & 1<<b) for b in range(8)] even_odd = sum(bo) & 1
Seems to work, is there a better way to do this?
Well, if you were happy with your generator expression, you can use almost exactly the same syntax:
for c in range(128): even_odd = (sum([bool(c & 1<<b) for b in range(8)])) & 1
No need for the 'bo' variable...
STeVe -- http://mail.python.org/mailman/listinfo/python-list