On Jun 7, 8:30 pm, Some Other Guy <[EMAIL PROTECTED]> wrote: > [EMAIL PROTECTED] wrote: > > Hello all, > > I have two integers and I want to divide one by another, and want to > > get an integer result which is the higher side whenever the result is > > a fraction. > > 3/2 => 1 # Usual behavior > > some_func(3, 2) => 2 # Wanted > > Are you trying to accomplish int((a/b) + 0.5), but cheaply? > > If so, consider that that is the same as (a/b) + (b/2b), > which is (2a/2b) + (b/2b), which is (2a+b)/2b. > > Since this just involves doubling you can avoid multiplying altogether > and just use this: > > def rounddiv(a,b): > return int((a+a+b)/(b+b)) > > That's 3 integer adds and 1 integer divide. The int() cast is just > there is case somebody passes in floats for a or b; if you know you're > only going to have integer arguments you don't need it.
The // operator was added to the language for a reason. I'm surprised at how few Pythonistas are using it six years later. -- http://mail.python.org/mailman/listinfo/python-list
