On Jun 7, 1:19 pm, dmitrey <[EMAIL PROTECTED]> wrote:
> On Jun 7, 10:18 am, Gerard Flanagan <[EMAIL PROTECTED]> wrote:> On Jun 7,
> 8:39 am, dmitrey <[EMAIL PROTECTED]> wrote:
>
> Thank you.
> And what is the simplest way (without split/join, if exist) to obtain
> name of directory parent to directory my_directory_name?
>
> Thx, D.
>
>>> os.path.join(os.pardir, os.path.dirname('/a/b/c/d/e/f.log'))
'/a/b/c/d/e'
>>> os.path.join(os.pardir, os.path.dirname(_))
'/a/b/c/d'
>>> os.path.join(os.pardir, os.path.dirname(_))
'/a/b/c'
>>> os.path.join(os.pardir, os.path.dirname(_))
'/a/b'
>>> os.path.join(os.pardir, os.path.dirname(_))
'/a'
>>> os.path.join(os.pardir, os.path.dirname(_))
'/'
>>> os.path.join(os.pardir, os.path.dirname(_))
'/'
(When using the interactive interpreter, an underscore '_' means 'the
previous result')
HTH
Gerard
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