Erik Max Francis wrote: > Wildemar Wildenburger wrote: > > >> So in each term of the sum you have a derivative of f, which in the >> case of the sine function translates to sine and cosine functions at the >> point 0. It's not like you're rid of the function just by doing a >> polynomial expansion. The only way to *solve* this is to forbid x from >> having a dimension. At least *I* see no other way. Do you? >> > > That was precisely his point. The Maclaurin series (not MacLaurin) only > makes any sense if the independent variable is dimensionless. And thus, > by implication, so it is also the case for the original function. > > No that was not his point. Maybe he meant it, but he said something profoundly different. To quote:
[EMAIL PROTECTED] wrote: > if we expand sine in taylor series sin(x) = x - (x3)/6 + (x5)/120 etc. > you can see that sin can be dimensionless only if x is dimensionless too. This argumentation gives x (and sin(x)) the option of carrying a unit. That however is *not* the case. This option does not exist. Until someone proves the opposite, of course. Geez, I love stuff like that. Way better than doing actual work. :D /W (PS: THX for the MacLaurin<>Maclaurin note. I can't help that appearantly; I also write 'LaGrange' all the time.) -- http://mail.python.org/mailman/listinfo/python-list
