I'm writing a python program to open a file, and display it onscreen, but I can't seem to find the var that "tkOpenFileName" returns to. It's not much use if you can't get the filename you just chose, so there must be a way to get it. Could anyone help me?
Thanks, Alex
openfilename=tkFileDialog.askopenfilename(filetypes=[("all files", "*")])
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Vincent Wehren -- http://mail.python.org/mailman/listinfo/python-list
