Orlando Döhring a écrit : > ... > A = [ 3 7 5 > 0 4 2 ]; > > # in Python: A = [[3,7,5],[0,4,2]] > > [B,IX] = sort(A,2) > > # sort by rows > > B = > 3 5 7 > 0 2 4 > > IX = > 1 3 2 > 1 3 2 > > # first line: 3 was formerly in the first position, 5 formerly in > position 3, 7 formerly in position 2 > # second line: similiarly > >
Like this : In [122]: l=[[3,2,1], [4,6,5,0]] In [123]: from operator import itemgetter In [124]: [ list(sorted(enumerate(e), key=itemgetter(1))) for e in l ] Out[124]: [[(2, 1), (1, 2), (0, 3)], [(3, 0), (0, 4), (2, 5), (1, 6)]] except the old position is the first element of each tuple, you may have the same order with this one : In [126]: [ list((pos, elt) for pos, elt in sorted(enumerate(e), key=itemgetter(1))) for e in l ] Out[126]: [[(1, 2), (2, 1), (3, 0)], [(0, 3), (4, 0), (5, 2), (6, 1)]] -- http://mail.python.org/mailman/listinfo/python-list
