here's another interesting algorithmic exercise, again from part of a larger program in the previous series.
Here's the original Perl documentation: =pod merge($pairings) takes a list of pairs, each pair indicates the sameness of the two indexes. Returns a partitioned list of same indexes. For example, if the input is merge( [ [1,2], [2,4], [5,6] ] ); that means 1 and 2 are the same. 2 and 4 are the same. Therefore 1==2==4. The result returned is [[4,2,1],[6,5]]; (ordering of the returned list and sublists are not specified.) =cut For those of you unfamiliar with math lingoes, partition a list means to create sublists, based on some criteria. In our case, the input list comes in the form of pairs, and its members are the union of all members in the pairs. The criterion for partition in our case is that of equivalence, specified in the pairs input. Try to write a Python code for this. In the Python code, the input should be a list of couples. (for Perlers, sketch out the algorithm on paper and try to code in Python directly.) I'll post Perl & Python code tomorrow. ==This is brought to you by the Perl-Python community.== == http://xahlee.org/perl-python/python.html == Xah [EMAIL PROTECTED] http://xahlee.org/PageTwo_dir/more.html -- http://mail.python.org/mailman/listinfo/python-list