The logger objects findCaller() method is returning a "3" element
tuple instead of "2" two as
documented in the 2.4.4 Python Library Reference .DocString is showing
it correctly.
findCaller()
Finds the caller's source filename and line number. Returns the
filename and line number as a 2-element tuple.
[EMAIL PROTECTED] python]$ python
Python 2.4.4 (#1, Feb 2 2007, 17:43:17)
[GCC 3.4.3 20041212 (Red Hat 3.4.3-9.EL4)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import logging
>>> logging.basicConfig()
>>> logger = logging.getLogger()
>>> help(logger.findCaller)
Help on method findCaller in module logging:
findCaller(self) method of logging.RootLogger instance
Find the stack frame of the caller so that we can note the source
file name, line number and function name.
>>> logger.findCaller()
('<stdin>', 1, '?')
>>>
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